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If the normal to differentiable curve y = f(x) at x = 0 be given by the equation `3x-y + 3 = 0`, then the value of `lim_(x->0)` `x^2/(f(x^2)-5f(4x^2)+ 4f(7x^2))` is

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If the normal to differentiable curve y=f(x) at x=0 be given by the equation 3x-y+3=0, then the value of lim_(x rarr0)(x^(2))/(f(x^(2))-5f(4x^(2))+4f(7x^(2))) is

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If the equation of the normal to the curve y=f(x) at x =0 is 3x-y+3=0 then the value of lim_(x rarr0)(x^(2))/({f(x^2)-5f(4x^(2))+4f(7x^(2))}) is

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