((:m)/(3)+8=(m)/(2)-1

(m-1)/(m-4)=(2m-3)/(3m-8)

If log_(8)m+log_(8).(1)/(6)=(2)/(3) , then m is equal to

If log_(8)m + log_(6) (1)/(6) = (2)/(3), then m is equal to

The lines y=m_1x ,y=m_2xa n dy=m_3x make equal intercepts on the line x+y=1. Then (a) 2(1+m_1)(1+m_3)=(1+m_2)(2+m_1+m_3) (b) (1+m_1)(1+m_3)=(1+m_2)(1+m_1+m_3) (c) (1+m_1)(1+m_2)=(1+m_3)(2+m_1+m_3) (d) 2(1+m_1)(1+m_3)=(1+m_2)(1+m_1+m_3)