[" cosa "sin(beta-gamma)+cos beta sin(gamma-alpha)+],[" as "7sin(alpha-beta)=quad [E-2003]],[" ji "quad " 2) "I/2],[" i) "144050cos theta" cos "]

cos alpha sin (beta-gamma)+cos beta sin (gamma-alpha) +cos gamma(sin alpha-beta)=

cos alpha sin (beta-gamma) + cos beta sin (gamma-alpha) + cos gamma sin (alpha-beta)=

cos alpha sin (beta-gamma)+cos betasin (gamma-alpha+cos gamma sin (alpha-beta)=

cos alpha sin (beta-gamma) + cos beta sin (gamma-alpha) + cos gamma sin (alpha-beta) =

cos alpha * sin (beta - gamma ) + cos beta * sin ( gamma - alpha ) + cos gamma * sin ( alpha - beta )=

cos (alpha + beta) cos gamma-cos (beta + gamma) cos alpha = sin beta sin (gamma-alpha)

If cos (beta - gamma) + cos (gamma - alpha) + cos (alpha - beta) = -3/2, "show that", cos alpha + cos beta + cos gamma = 0 "and" sin alpha + sin beta + singamma = 0."Hence deduce that," cos (beta - gamma) = cos (gamma - alpha) = cos (alpha - beta) = -1/2.

lf, cos (x + alpha) cos (x + beta), cos (x + gamma) sin (x + alpha), sin (x + beta), sin (x + gamma) sin (beta + gamma), sin ( gamma-alpha), sin (alpha-beta) then (Given alpha! = beta! = gamma), sin (alpha-beta)

If cos alpha + cos beta + cos gamma =3 , " then " sin alpha + sin beta + sin gamma =