" iding on lionizontal tee with iscoerty of "3" the "s" is stopped by frietiou in "10" see "" what "3" in coefficient of frietion between sto "

A block of mass 2kg lying on ice when given a velocity of 6ms^(-1) is stopped by friction in 5s. The coefficient of friction between the block and ice is (g=10 ms^(-2) )

Coefficient of x^(10) in e^(3x) is

A marble block of mass 2 kg lying on ice when given a velocity of 6m//s is stopped by friction in 10s. Then the coefficient of friction is

A marble block of mass 2 kg lying on ice when given a velocity of 6m//s is stopped by friction in 10s. Then the coefficient of friction is

A marble block of mass 2 kg lying on ice when given a velocity of 6m//s is stopped by friction in 10s. Then the coefficient of friction is