Consider 8 vertices of a regular octagon and its centre. If T denotes the number of triangles and S denotes the number of straight lines that can be formed with these 9 points then the val of (T - S) =

If P denotes the perimeter and S denotes the sum of the distances of a point within a triangle from its angular points, then

A, B, C, D and E are coplanar points and three of them lie in a straight line. What is the maximum number of triangles that can be drawn with these points as their vertices ?

There are 25 points in a plane,of which 10 are on the same line.Of t with any of the first ten points.The number of different straight lines that can be formed by joining these points is (a) 256 (c) 255

There are 10 points in a plane, no three of which are in the same straight line, except 4 points, which are collinear. Find (i) the number of lines obtained from the pairs of these points, (ii) the number of triangles that can be formed with vertices as these points.

Let N denotes,the greatest number of points in which m straight lines and n circles intersect. Then,

There are 10 points on a straight line AB and 8 on another straight line AC, none of them being A. How many triangles can be formed with these points as vertices?

Consider a regular polygon with 10 sides, What is the number of triangles that can be formed by joining the vertices which have no common side with any of the sides of the polygon?