" The value of "int_(-1)^(1)log((x-1)/(x+1))dx" is "

int_(-1)^(1)log((1+x)/(1-x))dx=

int_(-1)^(1)log((1+x)/(1-x))dx=

int_(-1)^(1)log[(a-x)/(a+x)]dx

The value of int_(0)^(1)(log(1+x))/(1+x^(2))dx is

Evaluate int_(1)^(2)(log(x+1))/(x+1)dx

Prove that int_(0)^(1)log((x)/(x-1))dx=int_(0)^(1)log((x-1)/(x))dx . Find the value of int_(0)^(1)log((x)/(x-1))dx

The value of int_(1)^(e)(1)/(x)(1+log x)dx is

The value of int_(0)^(1) (8 log(1+x))/(1+x^(2)) dx is

The value of int_(0)^(1) (log(1+x)dx)/(1+x^(2)) is -

int_(0)^(1)(log(1+x))/(1+x)dx