[" If "x=a sin(omega t+(pi)/(6))" and "x'=a cos omega t," then find the phase "],[" difference between two waves."],[O pi],[0 pi/2],[0 pi/3],[0 pi/6]

If x=a sin(omegat+(pi)/6) and x= a cos omegat , then what is the phase difference between the two waves?

if x = a sin (omegat + pi//6) and x' = a cos omega , t, then what is the phase difference between the two waves

When two waves y _(1) =A sin (omega t + (pi)/(6)) and y _(2) = A cos (omega t) superpose, find amplitude of resultant wave.

Two sinusoidal current are given by i_(1)=20 sin (omega t +(pi)/6) and i_(2)=10 sin(omega t-(pi)/4) The pahase difference between them is

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

Two particles are executing S.H.M. according to the equations x_1 = 6 sin (10 pi t+ pi/3) and x_2 = 6 sin (8 pi t + pi/4) .Then the phase difference between the first and second particle at t = 0.5 s will be

Two waves are represented by y_(1)=a_(1)cos (omega t - kx) and y_(2)=a_(2)sin (omega t - kx + pi//3) Then the phase difference between them is-