An aqueous solution of Mohr's salt can give a precipitate with NaOH or `NH_(4)OH`. But the aqueous solution of potassium ferrocyanide cannot give a precipitate with both reagents. How do you account for this ?

Explanation

To understand why an aqueous solution of Mohr's salt can give a precipitate with NaOH or NH4OH, while potassium ferrocyanide cannot, we need to analyze the nature of these compounds and their reactions with bases.

### Step-by-Step Solution:

1. **Identify Mohr's Salt**:
- Mohr's salt is a double salt with the formula \( (NH_4)_2Fe(SO_4)_2 \cdot 6H_2O \). It consists of two different cations: ammonium \( (NH_4^+) \) and ferrous \( (Fe^{2+}) \).

2. **Reactions with Bases**:
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