Assuming that `2NO + O_(2) to 2NO_(2)` is a single-step reaction, what will be the rate of reaction when the volume of the reaction vessel is reduced of `1//4^(th)` of the initial value ? The original rate of reaction is 64 mol/L/s.

Explanation

To solve the problem step by step, we will analyze the reaction and the effect of changing the volume of the reaction vessel on the rate of reaction.

### Step 1: Understand the Reaction
The reaction given is:
\[ 2NO + O_2 \rightarrow 2NO_2 \]

This is a single-step reaction, and we can express the rate of reaction (R) in terms of the concentrations of the reactants.

...