During electrolysis of molten `PbBr_(2)`, _____ fumes are liberated at the anode.

Answer

To solve the question regarding the electrolysis of molten PbBr₂ and the fumes liberated at the anode, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Electrolyte**: The electrolyte in this case is molten lead(II) bromide, PbBr₂.

2. **Dissociation of Electrolyte**: When PbBr₂ is molten, it dissociates into its ions:
\[ \text{PbBr}_2 \rightarrow \text{Pb}^{2+} + 2\text{Br}^- \]

3. **Electrolysis Process**: During electrolysis, the Pb²⁺ ions migrate to the cathode (negative electrode), and the Br⁻ ions migrate to the anode (positive electrode).

4. **Reactions at the Electrodes**:
- **At the Cathode**: The Pb²⁺ ions gain electrons (reduction) and are deposited as lead:
\[ \text{Pb}^{2+} + 2e^- \rightarrow \text{Pb (s)} \]
- **At the Anode**: The Br⁻ ions lose electrons (oxidation) and form bromine gas:
\[ 2\text{Br}^- \rightarrow \text{Br}_2 + 2e^- \]

5. **Fumes Liberation**: The bromine gas (Br₂) produced at the anode is released as fumes.

### Final Answer:
During the electrolysis of molten PbBr₂, **bromine (Br₂) fumes are liberated at the anode**.

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