Which of the following electrolytes exhibits maximum conductivity ?

Options

A. 1 M NaCl
B. 1 M KCl
C. `1 M Ca(ON_(3))_(2)`
D. 1 M `Al_(2) (SO_(4))_(3)`

Answer

To determine which electrolyte exhibits maximum conductivity, we need to analyze the dissociation of each given electrolyte and count the number of ions produced in solution. The more ions produced, the higher the conductivity.

### Step-by-Step Solution:

1. **Identify the Electrolytes**: The electrolytes given are:
- 1 M NaCl
- 1 M Ca(NO3)2
- 1 M Al2(SO4)3

2. **Dissociation of NaCl**:
- NaCl dissociates into:
\[ \text{NaCl} \rightarrow \text{Na}^+ + \text{Cl}^- \]
- Total ions produced: 2 ions (1 Na⁺ and 1 Cl⁻).

3. **Dissociation of Ca(NO3)2**:
- Ca(NO3)2 dissociates into:
\[ \text{Ca(NO}_3\text{)}_2 \rightarrow \text{Ca}^{2+} + 2\text{NO}_3^- \]
- Total ions produced: 3 ions (1 Ca²⁺ and 2 NO₃⁻).

4. **Dissociation of Al2(SO4)3**:
- Al2(SO4)3 dissociates into:
\[ \text{Al}_2(\text{SO}_4)_3 \rightarrow 2\text{Al}^{3+} + 3\text{SO}_4^{2-} \]
- Total ions produced: 5 ions (2 Al³⁺ and 3 SO₄²⁻).

5. **Comparison of Conductivity**:
- NaCl produces 2 ions.
- Ca(NO3)2 produces 3 ions.
- Al2(SO4)3 produces 5 ions.

6. **Conclusion**:
- Since Al2(SO4)3 produces the highest number of ions (5), it exhibits the maximum conductivity among the given electrolytes.

### Final Answer:
The electrolyte that exhibits maximum conductivity is **Al2(SO4)3**.