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If the surds root(4)(4), root(6)(5), roo...

If the surds `root(4)(4), root(6)(5), root(8)(6) and root(12)(8)` are arranged in ascending order from left to right, then the third surd from the left is

A

`root(12)(8)`

B

`root(4)(4)`

C

`root(8)(6)`

D

`root(6)(5)`

Text Solution

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The correct Answer is:
To solve the problem of arranging the surds \( \sqrt[4]{4}, \sqrt[6]{5}, \sqrt[8]{6}, \sqrt[12]{8} \) in ascending order, we will follow these steps: ### Step 1: Rewrite the surds in exponential form We can express each surd in terms of powers: - \( \sqrt[4]{4} = 4^{1/4} \) - \( \sqrt[6]{5} = 5^{1/6} \) - \( \sqrt[8]{6} = 6^{1/8} \) - \( \sqrt[12]{8} = 8^{1/12} \) ### Step 2: Convert the bases to powers of 2 Next, we will express the bases in terms of powers of 2: - \( 4 = 2^2 \) so \( 4^{1/4} = (2^2)^{1/4} = 2^{2/4} = 2^{1/2} = \sqrt{2} \) - \( 5 \) remains \( 5^{1/6} \) - \( 6 = 2 \cdot 3 \) so \( 6^{1/8} = (2 \cdot 3)^{1/8} = 2^{1/8} \cdot 3^{1/8} \) - \( 8 = 2^3 \) so \( 8^{1/12} = (2^3)^{1/12} = 2^{3/12} = 2^{1/4} \) ### Step 3: Compare the surds Now we have: - \( \sqrt{2} = 2^{1/2} \) - \( 5^{1/6} \) - \( 2^{1/8} \cdot 3^{1/8} \) - \( 2^{1/4} \) ### Step 4: Finding a common exponent To compare these surds, we can express them with a common exponent. The least common multiple of the denominators (4, 6, 8, 12) is 24. We will express each term with a power of \( 24 \): - \( \sqrt{2} = 2^{1/2} = 2^{12/24} \) - \( 5^{1/6} = 5^{4/24} \) - \( 2^{1/8} \cdot 3^{1/8} = 2^{3/24} \cdot 3^{3/24} \) - \( 2^{1/4} = 2^{6/24} \) ### Step 5: Rewrite the surds Now we can rewrite the surds: - \( 2^{12/24} \) - \( 5^{4/24} \) - \( 2^{3/24} \cdot 3^{3/24} \) - \( 2^{6/24} \) ### Step 6: Calculate the values We need to calculate the approximate values of these surds: - \( 2^{12/24} = 2^{0.5} \approx 1.414 \) - \( 5^{4/24} = 5^{0.1667} \approx 1.379 \) - \( 2^{3/24} \cdot 3^{3/24} = (2^{0.125} \cdot 3^{0.125}) \approx 1.1447 \) - \( 2^{6/24} = 2^{0.25} \approx 1.189 \) ### Step 7: Arrange in ascending order Now we can arrange these values in ascending order: 1. \( 2^{3/24} \cdot 3^{3/24} \approx 1.1447 \) 2. \( 2^{6/24} \approx 1.189 \) 3. \( 5^{4/24} \approx 1.379 \) 4. \( 2^{12/24} \approx 1.414 \) ### Conclusion The third surd from the left is \( \sqrt[6]{5} \).

To solve the problem of arranging the surds \( \sqrt[4]{4}, \sqrt[6]{5}, \sqrt[8]{6}, \sqrt[12]{8} \) in ascending order, we will follow these steps: ### Step 1: Rewrite the surds in exponential form We can express each surd in terms of powers: - \( \sqrt[4]{4} = 4^{1/4} \) - \( \sqrt[6]{5} = 5^{1/6} \) - \( \sqrt[8]{6} = 6^{1/8} \) - \( \sqrt[12]{8} = 8^{1/12} \) ...
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