A plot is in the shape of a trapezium. The parallel sides of the plot are 20 m and 16 m long, and the distance between them is 8 m. A square plot has the same area as the trapezium. A pit of dimensions 2.4 m long, 1.5 m wide, and 1 m deep is dug inside the trapezium plot and the soil is spread uniformly on the square plot. Find the rise in the level of hte plot.

Explanation

`"Area of trapezium"=(1)/(2)xx8xx(20+16)`
`=4xx36=144m^(2)`
`rArr" Area of the square plot"=144m^(2)`
Volume of the soil dugout `=2.4xx1.5xx1`
`"Rise in the level"=("Volume of the soil spread")/("Area of the square plot")`
`therefore" Rise in level"=(3.6)/(144)m=(360)/(144)cm=2.5cm`