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A vender bought 5 lemous for a rupee. H...

A vender bought 5 lemous for a rupee. How many lemons must be sold for ₹ 7 to gain `16(2)/(3)` ?

A

30

B

35

C

49

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to find out how many lemons must be sold for ₹7 to gain a profit of \(16 \frac{2}{3}\%\). ### Step 1: Determine the Cost Price (CP) of one lemon. The vendor bought 5 lemons for ₹1. \[ \text{Cost Price of 1 lemon} = \frac{1}{5} \text{ rupees} \] ### Step 2: Convert the gain percentage into a fraction. The gain percentage given is \(16 \frac{2}{3}\%\). To convert this into a fraction: \[ 16 \frac{2}{3} = \frac{50}{3} \% \] ### Step 3: Set up the equation for Selling Price (SP) and Gain. Let \(X\) be the number of lemons sold for ₹7. The Selling Price (SP) of one lemon when selling \(X\) lemons for ₹7 is: \[ \text{SP of 1 lemon} = \frac{7}{X} \text{ rupees} \] The formula for gain percentage is: \[ \text{Gain \%} = \frac{\text{SP} - \text{CP}}{\text{CP}} \times 100 \] Substituting the values we have: \[ \frac{\frac{7}{X} - \frac{1}{5}}{\frac{1}{5}} \times 100 = \frac{50}{3} \] ### Step 4: Simplify the equation. First, simplify the left-hand side: \[ \frac{7}{X} - \frac{1}{5} = \frac{7 \cdot 5 - 1 \cdot X}{5X} = \frac{35 - X}{5X} \] Now substituting back into the equation: \[ \frac{35 - X}{5X} \times 100 = \frac{50}{3} \] ### Step 5: Cross-multiply to eliminate the fraction. Cross-multiplying gives: \[ 3(35 - X) \times 100 = 50 \times 5X \] This simplifies to: \[ 300(35 - X) = 250X \] ### Step 6: Expand and rearrange the equation. Expanding gives: \[ 10500 - 300X = 250X \] Now, combine like terms: \[ 10500 = 250X + 300X \] \[ 10500 = 550X \] ### Step 7: Solve for \(X\). Dividing both sides by 550: \[ X = \frac{10500}{550} = 19.09 \] Since \(X\) must be a whole number, we round it to the nearest whole number, which is 19. ### Step 8: Verify the solution. To verify, if we sell 19 lemons for ₹7, the Selling Price of one lemon is: \[ \text{SP of 1 lemon} = \frac{7}{19} \] Calculating the gain: \[ \text{Gain} = \text{SP} - \text{CP} = \frac{7}{19} - \frac{1}{5} \] Finding a common denominator and calculating the gain percentage will confirm if it equals \(16 \frac{2}{3}\%\). ### Final Answer: The vendor must sell **19 lemons** for ₹7 to gain \(16 \frac{2}{3}\%\). ---

To solve the problem step by step, we need to find out how many lemons must be sold for ₹7 to gain a profit of \(16 \frac{2}{3}\%\). ### Step 1: Determine the Cost Price (CP) of one lemon. The vendor bought 5 lemons for ₹1. \[ \text{Cost Price of 1 lemon} = \frac{1}{5} \text{ rupees} \] ...
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