Let ABC be an isosceles triangle with base BC whose length is 'a'. If 'r ' is the radius of the circle inscribed in the `DeltaABC and r_1` be theradius of the circle escribed opposite to the angle A, then the product `rr_1` can be equal to

Let ABC be an isosceles triangle with base BC whose length is 'a'.If ' ' is the radius of the circle inscribed in the Delta ABC and r_(1) be theradius of the circle escribed opposite to the angle A,then the product rr_(1) can be equal to

Let ABC be an isosceles triangle with base BC. If r is the radius of the circle inscribsed in DeltaABC and r_(1) is the radius of the circle ecribed opposite to the angle A, then the product r_(1) r can be equal to (where R is the radius of the circumcircle of DeltaABC )

Find the area of right triangle if it is known that the radius of the circle inscribed in the triangle is r and that of the circumscribed circle is R.

ABC is an isosceles triangle inscribed in a circle. If AB = AC 12sqrt""5 and BC = 24 cm then radius of circle is:

If r is the radius of inscribed circle of a regular polygon of n-sides ,then r is equal to

In triangle ABC,right angled at B, BC = 24 cm, and AB = 7 cm. A circle is inscribed in triangle ABC. Then the radius of the circle is: