यदि `x=a(costheta+thetasintheta),y=a(sintheta-thetacostheta) तब(dy)/(dx)`=

If x=a(costheta+thetasintheta),y=a(sintheta-thetacostheta)," then "(dy)/(dx)=

Find (dy)/(dx) , if x=a(costheta+thetasintheta) , y=a(sintheta-thetacostheta)

Find dy/dx of x=a(costheta+thetasintheta) , y=a(sintheta-thetacostheta)

The normal to he curve x=a(costheta+thetasintheta),y=a(sintheta-thetacostheta) at any point 'theta' is such that

The normal to the curve x=a(costheta+thetasintheta),y=a(sintheta-thetacostheta) at any point theta is such that

Consider the curve x=a(cos theta+thetasintheta) and y=a(sin theta-thetacostheta) . What is (dy)/(dx) equal to ?

Find y_2 in each of the following cases: x=a(costheta+thetasintheta),y=a(sintheta-thetacostheta) at theta=pi/4

Consider the curve x=a(cos theta+thetasintheta) and y=a(sin theta-thetacostheta) . what is (d^(2)y)/(dx^(2)) equal to ?

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=a(costheta+thetasintheta), y=a(sintheta-thetacostheta)