The angular position of a line of a disc of radius r = 6cm is given by `theta=10 - 5t +4t^2` rad , the average angular velocity between 1 and 3s is

The angular position of a point on the rim of a rotating wheel is given by theta=4t^(3)-2t^(2)+5t+3 rad. Find (a) the angular velocity at t=1 s , (b) the angular acceleration at t=2 s . (c ) the average angular velocity in time interval t=0 to t=2 s and (d) the average angular acceleration in time interval t=1 to t=3 s .

The angular displacement of a particle is given by theta =t^3 + t^2 + t +1 then, its angular velocity at t=2 sec is …… rad s^(-1)

The angular displacement of particle (in radian) is given by theta=t^(2) + t . Calculate angular velocity at t=2 second.

The angular position of a particle revolving about an axis is given by Ɵ(t) = t^2 - 3t + 4 radian. Find the acceleration of the point at time t = 2 s. Given radius of circular path is 1 m

The angular position of a particle revolving about an axis is given by Ɵ(t) = t^2 - 3t + 4 radian. Find the acceleration of the point at time t = 2 s. Given radius of circular path is 1 m

The angular displacement of a particle is given by theta=t^(3)+ t^(2)+ t+1 then, its angular velocity at t = 2sec is ……….. rad s^(-1)

The angular displacement of a particle is given by theta=t^(3)+ t^(2)+ t+1 then, its angular velocity at t = 2sec is ……….. rad s^(-1)

The angular displacement of a body is given by theta = 2t^(2) + 5t -3 . Find the value of the angular velocity and angular acceleration when t = 2s.

The angular position of a point on a rotating wheel is given by theta=2.0+4.0t^(2)+2.0t^(3) , where theta is in radians and t is in seconds. At t = 0, what are (a) the point's angular position and (b) its angular velocity? ( c) What is its angular velocity at t = 3.0 s? (d) Calculate its angular acceleration at t = 4.0 s. (e) Is its angular acceleration constant?