The speed of a particle executing SHM with amplitude of displacement 5 cm is `3 cm //s ` at a distance 2.5 cm from mean position. What will be its speed at a distance `2.5 sqrt(3)` from mean position?

A particle executing a SHM has maximum acceleration at a distance of 0.5 cm from its mean position is 2cm//s^(2) . What will be its velocity when it is at a distance of 1 cm from its mean position.

A particle executing SHM has amplitude of 4cm, and its acceleration at a distance of 1cm from the mean position is 3cm^(-2) . What will its velocity be when it is at a distance of 2 cm from its mean position?

If particle executing S.H.M. has an amplitude of 6 cm, its acceleration at a distance 2 cm from mean position is 8 cm/s^2 , then the maximum speed of the particle will be

A particle is executing simple harmonic motion. The velocity of the particle is 10 m s^(-1) . What at a distance of 5 cm from mean position and 8 cm s^(-1) when at a distance of 12 cm from mean position. What will be the amplitude of motion ?

The acceleration of a particle performing SHM is 12cm//s^2 at a distance of 3 cm from the mean position. Calculate its time-period.

The acceleration of a particle performing S.H.M. is 12 cm // sec^(2) cm at a distance of 3 cm form the mean position. Its period is