यदि सदिश `vec(A),vec(B)` तथा `vec(C)` क्रमशः 12,5 तथा 13 मात्रक के है तथा `vec(A)+vec(B)=vec(C)` तो `vec(A)` व `vec(B)` बीच कोण है ?

The magnitude of vector vec(A),vec(B) and vec(C ) are respectively 12,5 and 13 unit and vec(A)+vec(B)= vec(C ) then the angle between vec(A) and vec(B) is

The magnitude of vector vec(A),vec(B) and vec(C ) are respectively 12,5 and 13 unit and vec(A)+vec(B)= vec(C ) then the angle between vec(A) and vec(B) is

If vec(a)=vec(b)+vec(c ) , then |vec(a)|=|vec(b)+vec(c )| .

[vec a + vec b vec b + vec c vec c + vec a] =

If 13 vec(a)= 3vec(i) + 4vec(j)+ 12vec(k), 13vec(b)= 4vec(i)-12vec(j) + 3vec(k), 13vec(c )=12vec(i) + 3vec(j)-4vec(k) , then vec(a) xx vec(b) =

If vec(a), vec(b) and vec(c) are three vectors such that vec(a) + vec(b) + vec(c) = vec(0) , then prove that vec(a) xx vec(b) = vec(b) xx vec(c) = vec(c) xx vec(a) .

The vectors vec(a),vec(b),vec (c ) are such that vec(a) + vec(b) + vec ( c ) = vec(0) . If |vec(a)| = 3 , |vec(b)|= 4 and |vec(c )|= 5 , show that vec(a).vec(b) +vec(b) .vec(c ) + vec (c ) . vec(a) = - 25

Let vec(a), vec(b), vec(c ) be such that vec(c ) ne vec(0), vec(a) xx vec(b)= vec(c ) and vec(b) xx vec(c )= vec(a) then show that vec(a), vec(b) and vec(c ) are pairwise perpendicular, |vec(b)|=1 and |vec(c )|= |vec(a)| .