Two vectors `vecP and vecQ` lie one plane. Vectors `vecR` lies in a differenct plane. In such a case, `vecP + vecQ + vecR`

Two vectors vecP and vecQ are having their magnitudes in the ratio sqrt(3) :1. Further । vecP+vecQ । =। vecP - vecQ। then the angle between the vectors (vecP+ vecQ) and (vecP - vecQ) is

Two vectors vecP and vecQ are having their magnitudes in the ratio sqrt(3) :1. Further । vecP+vecQ । =। vecP - vecQ। then the angle between the vectors (vecP+ vecQ) and (vecP - vecQ) is

The vectors vecP and vecQ have equal magnitudes of vecP +vecQ is n times the magnitude of vecP-vecQ , then angle between vecP and vecQ is:

There vectors vecP, vecQ and vecR are such that vecP+vecQ+vecR=0 Vectors vecP and vecQ are equal in , magnitude . The magnitude of vector vecR is sqrt2 times the magnitude of either vecP or vecQ . Calculate the angle between these vectors .

Let vecq and vecr be non - collinear vectors, If vecp is a vector such that vecp.(vecq+vecr)=4 and vecp xx(vecq xx vecr)=(x^(2)-2x+9)vecq" then " +(siny)vecr (x, y) lies on the line

The resultant of two vectors vecP and vecQ is vecR . If the magnitude of vecQ is doubled, the new resultant becomes perpendicular to vecP , then the magnitude of vecR is

The resultant of two vectors vecP andvecQ is vecR . If the magnitude of vecQ is doudled, the new resultant becomes perpendicuar to vecP . Then the magnitude of vecR is :