A particle moves according to law `s=t^3-3t^2+3t+12`. The velocity when the acceleration is zero is

A particle moves according to the law s=t^3-6t^2+9t+ 15 . Find the velocity when t=0 .

A particle moves according to law s=t^(3)-6t^(2)+9t+15 . Find the velocity when t = 0.

If S=2+3t-t^(2)+t^(3) , then velocity when acceleration is zero is

A particle moves along a straight line such that its displacement at any time t is given by s= (t^3- 6t^3 +3t+4) metres. The velocity when the acceleration is zero is

A particle moves according to the law s= t^3-6t^2+9t +5 . The displacement of the particle at the time when its acceleration is zero is........ A) 9 B) -7 C) 7 D) 0

A particle moves along a straight line such that its displacement at any time t is given by x =t^3-6t^2 +3t +4 in m. The velocity when acceleration is zero is

A particle is moving along a line according to the law s=t^3-3t^2+5 . The acceleration of the particle at the instant where the velocity is zero is

A particle moves according to the law x=t^(3)-6t^(2)+9t+5 . The displacement of the particle at the time when its acceleration is zero, is

A particle moves so that the distance moved is according to the law s(t)=t^3/3-t^2+3 . At what time the velocity and acceleration are zero respectively?