If `3^(49)(x+i y)=(3/2+(sqrt(3))/2i)^(100)` and `x=k y` then `k` is: a.`-1//3` b. `sqrt(3)` c. `-sqrt(3)` d.`-1/(sqrt(3))`

x+iy=(1-i sqrt(3))^(100), then (x,y)=

sqrt (2x) -sqrt (3y) = 0sqrt (3x) -sqrt (3y) = 0

If 2x^(4)sqrt(2)=(sqrt(3)-1)+i(sqrt(3)+1), then x=

If sqrt(2):(1+sqrt(3))sqrt(6):x backslash thenbackslash x is equal to sqrt(3)+3 b.1-sqrt(3)c.1+sqrt(3)d.sqrt(3)-3

If i=sqrt(-)1, then 4+5(-(1)/(2)+(i sqrt(3))/(2))^(334)+3(-(1)/(2)+(i sqrt(3))/(2))^(365) is equal to (1)1-i sqrt(3)(2)-1+i sqrt(3)(3)i sqrt(3)(4)-i sqrt(3)

Tangents drawn from (2, 0) to the circle x^2 + y^2 = 1 touch the circle at A and B . Then (A) A-= (1/2, sqrt(3)/2) , B -= (-1/2, - sqrt(3)/2) (B) A-= (- 1/2, (-sqrt(3)/2) , B -= (1/2, sqrt(3)/2) (C) A-= (1/2, sqrt(3)/2) , B-= (1/2, - sqrt(3)/2) (D) A-= (1/2, - sqrt(3)/2), B-= (1/2, sqrt(3)/2)

If a,b,c real in G.P.then the roots of the equation ax^(2)+bx+c=0 are in the ratio (1)/(2)(-1+sqrt(3)) b.(1)/(2)(1-i sqrt(3)) c.(1)/(2)(-1-i sqrt(3)) d.(1)/(2)(1+i sqrt(3))

values (s)(-i)^((1)/(3)) is/are (sqrt(3)-i)/(2) b.(sqrt(3)+i)/(2)c .(-sqrt(3)-i)/(2)d.(-sqrt(3)+i)/(2)

if x=sqrt(3)+(1)/(sqrt(3)) and y=sqrt(3)-(1)/(sqrt(3)) then x^(2)-y^(2) is