A circular coil has 63 turns, each of radius 22cm. It is placed in the magnetic meridian. A current of 0.5A is passed through the coil. What is the deflectio of a compass needle placed at its center is `45^(@)`. Calcualte the intensity of the earth's horizontal field.

A circular coil with 10 turns of mean radius 10 cm is placed in the magnetic meridian. A current of 0.5 A is passed through the coil. What is the defelctioin of a compass needle placed at the center of the coil? If the coil is rotated, at wht angle will the needle placed to the plane of the coil? If the coil is rotated, at what angle will the needle set parallel to the plane of the coil?)H of earth's field = 30 Am^(-1)

A magnetic needle is arranged at the centre of a current carrying coil having 50 turns with radius of coil 20 cm arranged along magnetic meridian. When a current of 0.5mA is allowed to pass through the coil the deflection is observed to be 30^(@) . Find the horizontal component of earth's magnetic field

A magnetic needle is arranged at the centre of a current carrying coil having 50 turns with radius of coil 20cm arranged along magnetic meridian. When a current of 0.5mA is allowed to pass through the coil the deflection is observed to be 30°. Find the horizontal component of earth's magnetic field

A circular coil of wire is made phi of 100 turns, each of radius 8 cm if a current of 0.4A passes through of, what will be the magnetic field at the centre of the coil

A circular coil of 50 turns and radius 0.2 cm carries a current of 12 A. Find magnetic field at the centre of the coil.

A compass needle free to turn in a horizontal plane is placed at the centre of circular coil of 30 turns and radius 12 cm. The coil is in a vertical plane making an angle of 45° with the magnetic meridian. When the current in the coil is 0.35 A, the needle points west to east. (a) Determine the horizontal component of the earth's magnetic field at the location. (b) The current in the coil is reversed, and the coil is rotated about its vertical axis by an angle of 90° in the anticlockwise sense looking from above. Predict the direction of the needle. Take the magnetic declination at the places to be zero.

Calcualte the current in amperes through a circular loop of 40 turns and mean radius 5cm placed with its planein the magnetic meridian that will produce a deflection of 60^(@) in a compass needle placed at its center. (The value of horizontal induction = 3.5 xx 10^(-5)T)