Ground To Ground Projectile | Part 2

Projectile motion || Ground to Ground Projection || Projection from a Tower || Average Velocity in Projectile Motion

A ground to ground projectile is at point A at t = (T)/(3) , is at point B at t = (5T)/(6) and reaches the ground at t = T . The difference in heights between points A and B is

Basics of 2D motion: Resolving into x and y motion| General 2D problems (velocity and position at any time)| Ground to ground projectile: Time of flight| Max height| Range| Max range

Basics of 2D motion: Resolving into x and y motion| General 2D problems (velocity and position at any time)| Ground to ground projectile: Time of flight| Max height| Range| Max range

For ground to ground projectile motion equation of path is y=12x-3//4x^(2) . Given that g=10ms^(-2) . What is the range of the projectile ?

In ground to ground projectile motion under gravity, which of the following doesn't affect the time of flight ?

Equation of trajector of ground to ground projectile is y=2x-9x^(2) . Then the angle of projection with horizontal and speed of projection is : (g=10m//s^(2))

For ground to ground projectile, time take by a particle to ge point O to point C is T_(1) and during the same motion time taken by the particle to ge from A to B is T_(2) then height 'h' is :

The question given below consist of an assertion and the reason . Use the following key to choose appropriate answer: Assertion : There is a case of ground -to - ground projectile . When projectile is fired at an its path where instantaneous velocity becomes perpendicular to its initial velocity . Reason : In case of ground -to- ground projectile projected at an angle theta , maximum possible deviation is 2 theta ,