An aqueous solution contains both `Al^(3+)` & `Zn^(2+)`.To this solution `NH_(4)OH` is added in excess.

An aqueous solution containing NH_(4)Cl,FeCl_(3) and MnCl_(2) is treated with NH_4OH solution. The observation is that:

Explain the following : When NH_(4)Cl and NH_(4)OH are added to a solution containing both, Fe^(3+) and Ca^(2+) ions, which ion is precipitated first and why?

When NH_(4)Cl is added to a solution of NH_(4)OH :

When NH_(4)Cl is added to a solution of NH_(4)OH :

When NH_(4)Cl is added to a solution of NH_(4)OH :

When NH_(4)Cl is added to a solution of NH_(4)OH ,

A colourless solid A dissolves in water. The aqueous solution gives a white precipitate B when NaOH or NH_4 OH is added. B dissolves in excess of NaOH but not in excess of NH_4OH . BaCl2 solution added to a solution of A gives a white precipitate C which is insoluble in dilute HCI. A may be

A colourless solid A dissolves in water. The aqueous solution gives a white precipitate B when NaOH or NH_4 OH is added. B dissolves in excess of NaOH but not in excess of NH,OH. BaCl2 solution added to a solution of A gives a white precipitate C which is insoluble in dilute HCI. A may be

The solubility products of Al(OH)_(3) and Zn(OH)_(2) are 8.5xx10^(-23) and 1.8xx10^(-14) respectively. If NH_(4)OH is added to a solution containing Al^(3+) and Zn^(2+) ions, then substance precipitated first is: