Find the freezing point of a glucose solution whose osmotic pressure at `25^(@)C` is found to be 30 atm. `K_(f)` (water) `= 1.86 kg mol^(-1)K`.

Calculate the freezing point of an aqueous soltuion of non-electrolyte having an osmotic pressure 2.0 atm at 300 K . ( K'_(f) = 1.86 K mol^(-1) kg and S = 0.0821 litre atm K^(-1) mol^(-1) )

Calculate the freezing point of an aqueous solution of a non-electrolyte having an osmotic pressure 2.0 atm at "300 K. Kf = 1.86 k.kg.mol"^(-1.)" R = 0.0821 lit.atm.k"^(-1)" mol"^(-1)

Calculate the freezing point of an aqueous solution of a non-electrolyte having an osmotic pressure 2.0 atm at "300 K. Kf = 1.86 k.kg.mol"^(-1.)" R = 0.0821 lit.atm.k"^(-1)" mol"^(-1)

Calculate the freezing point of an aqueous solution of a non-electrolyte having an osmotic pressure 2.0 atm at "300 K. Kf = 1.86 k.kg.mol"^(-1.)" R = 0.0821 lit.atm.k"^(-1)" mol"^(-1)

1 m aq. Solution of a salt shows elevation in boiling point equal to 3 times of its K_(b) . Determine (i) Freezing point of solution (ii) Osmotic pressure at 27^(@)C K_(f) (water)=1.86 K kg "mole"^(-1)

An aqueous solution of urea has a freezing point of -0.515^@C . Predict the osmotic pressure (in atm) of the same solution at 37^@C . k_f = 1.86 k kg (mol)^(-1)

Calculate the freezing point of a solution containing 60 g glucose (Molar mass = 180 g mol^(-1) ) in 250 g of water . ( K_(f) of water = 1.86 K kg mol^(-1) )

Calculate the freezing point of a solution containing 60 g glucose (Molar mass = 180 g mol^(-1) ) in 250 g of water . ( K_(f) of water = 1.86 K kg mol^(-1) )