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If cosx/a=cos(x+theta)/b=cos(x+2theta)/c...

If `cosx/a=cos(x+theta)/b=cos(x+2theta)/c=cos(x+3theta)/d` then `(a+c)/(b+d)` is equal to `(A)a/d (B)c/d (C)b/c (D)d/a`

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