A square with diagonals meeting at origin has (4,5) as one of its vertices.The vertex of this square which is in `2^( nd )`quadrant is

In a square ABCD, the diagonals meet at point O. The DeltaAOB is

A square is inscribed in the circle x^(2)+y^(2)-6x+8y-103=0 with its sides parallel to the coordinate axes. Then the distance of the vertex of this square which is nearest to the origin is

Origin is the centre of the square with one of its vertices at (3,4) then the other vertices are

One side of a square is inclined to the x-axis at an angle alpha and one of its extremities is at the origin. If the side of the square is 4 , find the equations of the diagonals of the square.

One diagonal of a square is 3x-4y+8=0 and one vertex is (-1,1), then the area of square is

If two vertices of a triangle are (0,2) and (4,3) and its orthocentre is (0,0) then the third vertex of the triangle lies in (a) 1^(st) quadrant (b) 2^(nd) triangle lies in (a) 1^(st) 4^(th) quadrant

The point of intersection of diagonals of a square ABCD is at the origin and one of its vertices is at a(4,2). What is the equation of the diagonal BD?