In displacement method, the distance between object and screen is 96 cm. The ratio of length of two images formed by a convex lens placed between them is 4.84.

In displacement method, the distance between object and screen is 96cm. The ratio of lengths of two images formed by a converging lens placed between them is 4. Then,

In the displacement method the distance between the object and the screen is 70 cm and the focal length of the lens is 16 cm, find the seperation of the magnified and diminished image position of the lens.

In a displacement method the distance between the object and the screen is 70 cm and the focal length of the lens is 16 cm, find the separations of the magnified and diminished image position of the lens.

The least distance between a point object and its real image formed by a convex lens of focal length F is

The distance between an object and its real image formed by a convex lens cannot be

In displacement method distance of object and screen is 100 cm initial image is obtained on screen. Now lens is displaced 40 cm image formed on screen again . If power of the lens is (100/N) dioptre, then find the value of N :

In the displacement method , a convex lens is placed in between an object and a screen . If one of them magnification is 3 and the displacement of the lens between the two positions is 24 cm , then the focal length of the lens is :-

A convex lens of focal length f is placed somewhere in between an object and a screen. The distance between the object and the screen is x . If the numerical value of the magnification produced by the lens is m , then the focal lnegth oof the lens is .