If `cos(theta_(1)-(pi)/(4))+sin(theta_(2)+(pi)/(2))+cos(theta_(3)-(pi)/(3))+3=0`, then `tan theta_(1)+tan theta_(2)+tan theta_(3)` is: (where `theta_(1),theta_(2),theta_(3)in(0,2 pi))`

IF 2 sin ( theta +(pi)/(3)) = cos (theta -(pi)/(6)), then tan theta =

If 2sin(theta+(pi)/(3))=cos(theta-(pi)/(6)) then tan theta =

If (cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))+(cos(theta_(3)+theta_(4)))/(cos(theta_(3)-theta_(4)))=0, then tantheta_(1)tan theta_(2)tan theta_(3)tan theta_(4)=

f theta_(1),theta_(2),theta_(3),theta_(4),theta_(5)in(0,(pi)/(2)), satisfying tan theta_(1)tan theta_(2)tan theta_(3)tan theta_(4)tan theta_(5)=1 then maximum_(2 value of )theta_(3)tan theta_(4)cos theta_(5) is cos theta_(1)cos theta_(2)cos theta_(3)cos theta_(4)cos theta_(5) is

If (a cos theta_(1),a sin theta_(1)),(a cos theta_(2),a sin theta_(2)) and (a cos theta_(3),a sin theta_(3)) represent the vertices of an equilateral triangle inscribed in a circle,then (a)cos theta_(1)+cos theta_(2)+cos theta_(3)=0 (b) sin theta_(1)+sin theta_(2)+sin theta_(3)=0(c)tan theta_(1)+tan theta_(2)+tan theta_(3)=0(d)cot theta_(1)+cot theta_(2)+cot theta_(3)=0

(cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))+(cos(theta_(3)+theta_(4)))/(cos(theta_(3)-theta_(4)))=0then(tan theta_(1)*tan theta_(2))/(cot theta_(2)*cot theta_(4))

If tan((pi)/(2) sin theta )= cot((pi)/(2) cos theta ) , then sin theta + cos theta is equal to

If cos theta_(1)+cos theta_(2)+cos theta_(3)=-3 where theta_(1),theta_(2),theta_(3)in[0,2 pi] then value sin((theta_(1))/(2))+sin((theta_(2))/(2))+sin((theta_(3))/(2)) is

If tan theta_(1),tan theta_(2),tan theta_(3) are the real roots of the x^(3)-(a+1)x^(2)+(b-a)x-b=0, where theta _(1)+theta_(2)+theta_(3)in(0,pi), then theta_(1)+theta_(2)+theta_(3) ,is equal to pi/2 b.pi/4c.3 pi/4d. pi