Two sound waves are represented by `y_(1)=sinomegat+cosomegat` and `y_(2)=(sqrt(3))/(2)sinomegat+(1)/(2)cosomegat`. The ratio of their amplitude is

Two SHM's are represented by y_(1) = A sin (omega t+ phi), y_(2) = (A)/(2) [sin omega t + sqrt3 cos omega t] . Find ratio of their amplitudes.

If two simple harmonic motions are given as x_(1)=Asin omegat andx_(2)=(A//2)sinomegat+(A//2)cosomegat , then the ratio of their amplitudes is

Two waves are represented by: y_(1)=4sin404 pit and y_(2)=3sin400 pit . Then :

Two simple harmonic motions are represented by y_(1)=5 [sin 2 pi t + sqrt(3)cos 2 pi t] and y_(2) = 5 sin (2pit+(pi)/(4)) The ratio of their amplitudes is

Two simple harmonic motions are represented as y_(1)=10 "sin" omega " and "y_(2)=5 "sin" wt +5 "cos" omega t The ration of the amplitudes of y_(1) " and " y_(2) is

If two waves represented by y_(1)=4sinomegat and y_(2)=3sin(omegat+(pi)/(3)) interfere at a point find out the amplitude of the resulting wave

Equations y_(1) A sinomegat and y_(2) = A/2 sin omegat + A/2 cos omega t represent S.H.M. The ratio of the amplitudes of the two motions is

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

Two simple harmonic motions are given by y _(1) = 5 sin ( omegat = pi //3). y_(2) = 5 ( sin omegat+ sqrt(3) cos omegat) . Ratio of their amplitudes is

Two wave are represented by the equations y_(1)=asinomegat ad y_(2)=acosomegat the first wave