A transverse wave is described by the equation
`y=A sin [2pi(ft-x//lambda)]`.
The maximum particle velocity is equal the wave velocity if :

A transverse wave is described by the equation y=A sin 2pi( nt- x//lambda_0) . The maximum particle velocity is equal to 3 times the wave velocity if

Transverse wave is described by the equation y=y_0 sin 2pi (ft-x/lambda) .The maximum particle velocity is twice the wave velocity if wavelength is____

A transverse wave is described by the equation y= A sin 2 pi (vt - x/lambda) . The maximum particle velocity is equal to four times the wave velocity if

A transverse wave is derscried by the equation y=y_(0) sin 2 pi (ft - (x)/(lamda)) . The maximum particle velocity is equal to four times the wave velocity if :-

A travelling wave is described by the equation y = y_(0) sin ((ft - (x)/lambda)) . The maximum particle velocity is equal to four times the wave velocity if

A transverse wave is described by the equation y=y_(0)sin4pi(upsilont-(x)/(lambda)) . The maximum particle velocity is equal to four times the wave velocity if

A transverse wave is given by y=A sin 2 pi ((t)/(T)-(x)/(lambda)) . The maximum particle velocity is equal to 4 times the wave velocity when

A simple harmonic wave is represent by the relation y(x,t)=a_(0) sin 2pi(vt-(x)/(lambda)) if the maximum particle velocity is three times the wave velocity, the wavelength lambda of the wave is

A travelling wave in a stretched string is described by the equation y = A sin (kx - omegat) the maximum particle velocity is