A stationary body explodes into four identical fragments such that three of them fly off mutually perpendicular to each other, each with same `KE, E_(0)`. The energy of explosion will be

A stationary body explodes in to four identical fragments such that three of them fly mutually perpendicular to each other, each with same KE(E_(0)) . The energy of explosion will be

A stationary body explodes in to four identical fragments such that three of them fly mutually perpendicular to each other, each with same KE(E_(0)) . The energy of explosion will be

A stationary body explodes in to four identical fragments such that three of them fly mutually perpendicular to each other, each with same KE(E_(0)) . The energy of explosion will be

A stationary body explodes into four identical fragments such that three of them fly off mutually perpendicular to each other, each with same K.E. E_(0) . The energy released in the explosion in the form of kinetic energy is NE_(0) . Find N

A body kept at rest explodes in four identical fragments and it is found that three of them move along mutually perpendicular directions with same kinetic energy K . Total energy released in the explosion is

1 kg body explodes into three fragements. The ratio of their masses is 1 : 1: 3 . The fragments of same mass move perpendicular to each other with speed 30 m/s. The speed of heavier part is

A stationary body of mass 3 kg explodes into three equal pieces. Two of the pieces fly off in two mutually perpendicular directions, one with a velocity of 3hati ms^(1) and the other with a velocity of 4hatj ms^(-1) . - If the explosion occurs in 10^(–4) s , the average force acting on the third piece in newton is

A stationary body of mass 3 kg explodes into three equal pieces. Two of the pieces fly off in two mutually perpendicular directions, one with a velocity of 3hati ms^(1) and the other with a velocity of 4hatj ms^(-1) . - If the explosion occurs in 10^(–4) s , the average force acting on the third piece in newton is