`y_(t)=2sin3pit`
`y_(2)=2sin(3pit-(pi)/(8))`
The wave velocity is

Two particle of medium disturbed by the wave propagation are at x_(1)=0 and x_(2)=1 cm . The respective displacement (in cm) of the particles can be given by the equation: y_(1)=2 sin 3pi t, y_(2)= 2 sin (3pi t-pi//8) the wave velocity is

two particle of medium disturbed by the wave propagation are at x_(1)=0 and x_(2)=1 cm . The respective displacement (in cm) of the particles can be given by the equation: y_(1)=2 sin 3pi t, y_(2) sin (3pi t-pi//8) the wave velocity is

two particle of medium disturbed by the wave propagation are at x_(1)=0cm and x_(2)=1 cm . The respective displacement (in cm) of the particles can be given by the equation: y_(1)=2 sin 3pi t, y_(2) sin (3pi t-pi//8) the wave velocity is

two particle of medium disturbed by the wave propagation are at x_(1)=0 and x_(2)=1 cm . The respective displacement (in cm) of the particles can be given by the equation: y_(1)=2 sin 3pi t, y_(2) sin (3pi t-pi//8) the wave velocity is

Two particles of a medium disturbed by the wave propagtion are at x_(1)=0 and x_(2)=1 cm The wave is propagating in positive x-direction The displacement of the particles is given by the equation: y_(1)=(2sin3pit) cm and y_(2)=2sin(3pit-pi//8) cm (t is in seconds)

The equation of displacement of two waves are given as y_(1)=10sin(3 pi t+(pi)/(3)) , y_(2)=10sin(3 pi t+(pi)/(3)) .Then what is the ratio of their amplitudes

Two simple harmonic motions are represented by y_(1)=5[sin2pit+sqrt(3)cos2pit] and y_(2)=5sin(2pit+(pi)/(4)) The ratio of their amplitudes is