A projectile thrown at an angle of `30^@` with the horizontal has a range `R_1` and attains a maximum height `h_1` Another projectile thrown, with the same velocity, at an angle `30^@` with the vertical, has a range `R_2` and attains a maximum height `h_2` The relation between `R_1 and R_2 ` is

A projectile is thrown at an angle of 40^@ with the horizontal and its range is R_1 Another projectile is thrown at an angle 40^@ with the vertical and its range is R_2 What is the relation between R_1 and R_2 ?

Show that maximum horizontal range is 4 times the maximum height attained by the projectile.

A projectile is thrown at an angle of 40^(@) with the horizontal and its range is R_(1) . Another projectile is thrown at an angle of 40^(@) with the vertical and its range is R_(2) . What is the relation between R_(1) and R_(2) ? (projection speed is same in both cases)

A stone projected with a velocity u at an angle q with the horizontal reaches maximum heights H_(1) . When it is projected with velocity u at an angle (pi/2-theta) with the horizontal, it reaches maximum height H_(2) . The relations between the horizontal range R of the projectile, H_(1) and H_(2) , is

(A projectile projected at an angle 30^(@) from the horizontal has a range R . If the angle of projection at the same initial velocity be 60^(@) , then the range will be