`(aA)^(-1)=1/aA^(-1)` where `a` is any real number and `A` is a square matrix.

(aA)^(-1)=(1)/(a)A^(-1) , where a is any real number and A is a square matrix.

(a.A)^(-1)=1/a.A^(-1) where a is any real number and A is square matrix

If A is any square matrix then AA' is a ………. Matrix.

If A is a square matrix then "AA" is

Let A be any 3xx 2 matrix show that AA is a singular matrix.

Consider a matrix A=[(0,1,2),(0,-3,0),(1,1,1)]. If 6A^(-1)=aA^(2)+bA+cI , where a, b, c in and I is an identity matrix, then a+2b+3c is equal to

Consider a matrix A=[(0,1,2),(0,-3,0),(1,1,1)]. If 6A^(-1)=aA^(2)+bA+cI , where a, b, c in and I is an identity matrix, then a+2b+3c is equal to

Let A be a nxxn matrix such that A ^(n) = alpha A, where alpha is a real number different from 1 and - 1. The matrix A + I_(n) is

Let A be a nxxn matrix such that A ^(n) = alpha A, where alpha is a real number different from 1 and - 1. The matrix A + I_(n) is

Let A be a nxxn matrix such that A ^(n) = alpha A, where alpha is a real number different from 1 and - 1. The matrix A + I_(n) is