`f(x)` is cubic polynomial with `f(x)=18a n df(1)=-1` . Also `f(x)` has local maxima at `x=-1a n df^(prime)(x)` has local minima at `x=0` , then the distance between `(-1,2)a n d(af(a)),` where `x=a` is the point of local minima is `2sqrt(5)` `f(x)` is increasing for `x in [1,2sqrt(5])` `f(x)` has local minima at `x=1` the value of `f(0)=15`

f(x) is cubic polynomial with f(x)=18 and f(1)=-1. Also f(x) has local maxima at x=-1 and f'(x) has local minima at x=0, then the distance between (-1,2) and (af(a)), where x=a is the point of local minima is 2sqrt(5)f(x) has local increasing for x in[1,2sqrt(5)]f(x) has local minima at x=1 the value of f(0)=15

Let f(x) be a cubic polynomial with f(1) = -10, f(-1) = 6, and has a local minima at x = 1, and f'(x) has a local minima at x = -1. Then f(3) is equal to _________.

f(x) is a cubic function with f(1)=-6,\ f(-1)=10 , and has maxima at x=-1. Also, f^(prime)(x) has minima at x=1. Find f(x)dot

Let f(x) be a polynomial of degree 3 having a local maximum at x=-1. If f(-1)=2,\ f(3)=18 , and f^(prime)(x) has a local minimum at x=0, then distance between (-1,\ 2)a n d\ (a ,\ f(a)), which are the points of local maximum and local minimum on the curve y=f(x) is 2sqrt(5) f(x) is a decreasing function for 1lt=xlt=2sqrt(5) f^(prime)(x) has a local maximum at x=2sqrt(5) f(x) has a local minimum at x=1

A cubic polynomial function f(x) has a local maxima at x=1 and local minima at x=0 .If f(1)=3 and f(0)=0, then f(2) is

let f(x)=(x^(2)-1)^(n)(x^(2)+x-1) then f(x) has local minimum at x=1 when

Let f(x)={(sin(pi x))/(2),0 =1f(x) has local maxima at x=1f(x) has local minima at x=1f(x) does not have any local extrema at x=1f(x) has a global minima at x=1