Two masses `2kg` and `5kg` are placed at points `'A'` and `'B'` as shown in the figure

`vecOA=2hati+3hatj`
`vecAB=5hati+8hatj`
Find the co-ordinates of centre of mass.

Three bodies of masses 5 kg, 4 kg and 2 kg have the position vectors as 2hati+3hatj-3hatk,hati+hatj+hatkand3hati-3hatj-4haktk . Find the coordinates of centre of mass.

If veca=hati+4hatj, vecb=2hati-3hatj, vecc=5hati+9hatj" then "vecc is equal to

The two vectors A=2hati+hatj+3hatk and B=7hati-5hatj-3hatk are -

Two bodies of masses 10kg and 2 kg are moving with velocities 2hati-7hatj+3hatk ms^(-1) and -10hati+ -35hatj-3hatk respectively. Find the velocity of the centre of mass.

Show that the vectors 2hati + 3hatj,5hati -5hatk and 6hatj + 4hatk are co-planar.

if a=2hati+hatj+2hattk and b=5hati-3hatj+hatk , then the projection of 'b' and 'a' is

The points with position vectors 60hati+3hatj, 40hati-8hatj and a hati-52 hatj are collinear if -

Three bodies of masses 3kg, 2kg and 1 kg kept at points (3hati+2hatj),(5hatj+hatk) and (2hati+hatk) respectively. Then the position vector of their centre of mass is given by

The position vector of two masses of 6 unit and 2 unit is (6hati-7hatj) & (2hati + 5hatj) respectively. Find out the position of their centre of mass.

If the points with position vectors 60hati+3hatj, 40 hati-8hatj and a hati - 52 hatj are collinear, then a =