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((1)/(1+cot^(2)A))=((1-tan A)/(1-cos A))...

((1)/(1+cot^(2)A))=((1-tan A)/(1-cos A))}_(z+tan^(2)A)

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Show that : ((1+tan^(2)A)/(1+cot^(2)A))=((1-tan A)/(1-cot A))^(2)=tan^(2)A

((1+tan^(2)A)/(1+cot^(2)A))=((1-tan A)/(1-cot A))^(2)=tan^(2)A

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(1+ tan^2 A)/(1+cot^2 A) = tan^2 A