Find the product of zeroes of quadratic polynomial `x^(2)+7x+10.`

Explanation

To find the product of the zeroes of the quadratic polynomial \( p(x) = x^2 + 7x + 10 \), we can follow these steps:

### Step 1: Identify the coefficients
The given polynomial is \( p(x) = x^2 + 7x + 10 \). Here, the coefficients are:
- \( a = 1 \) (coefficient of \( x^2 \))
- \( b = 7 \) (coefficient of \( x \))
- \( c = 10 \) (constant term)

### Step 2: Use the relationship between the roots and coefficients
For a quadratic polynomial of the form \( ax^2 + bx + c \), the product of the zeroes (roots) can be calculated using the formula:
\[ \text{Product of zeroes} = \frac{c}{a} \]

### Step 3: Substitute the values
Substituting the values of \( c \) and \( a \) into the formula:
\[ \text{Product of zeroes} = \frac{10}{1} = 10 \]

### Conclusion
Thus, the product of the zeroes of the polynomial \( x^2 + 7x + 10 \) is \( 10 \).

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