Home
Class 10
MATHS
ABCD is a trapizium with AB||DC. E and F...

ABCD is a trapizium with `AB||DC`. E and F are points on non - parallel sides AD and BC respecitively such that `EF||AB`, If AE = 3cm, ED = 4.8 cm, BF = 1.5 cm, then the value of CF is :

A

4.5 cm

B

2.4 cm

C

6.0 cm

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    MBD -HARYANA BOARD|Exercise FILL IN THE BLANKS|4 Videos
  • TRIANGLES

    MBD -HARYANA BOARD|Exercise SHORT ANSWER TYPES QUESTIONS|9 Videos
  • SURFACE AREAS AND VOLUMES

    MBD -HARYANA BOARD|Exercise LONG ANSWER TYPE QUESTIONS|16 Videos

Similar Questions

Explore conceptually related problems

ABCD is a trapezium with AB|DC.E and F are points on non-parallel sides AD and BC respectively such that EF is parallel to AB. Show that (AE)/(ED)=(BF)/(FC)

In DeltaABC,D and E are points on the sides AB and AC respectively ,such that DE||BC. If AD=2.5cm,BD=3cm and AE =3.75 cm , then the value of AC.

In DeltaABC , D and E are points on sides AB and AC respectively such that DE||BC . If AE=1.8cm, BD= 7.2cm and CE= 5.4cm, then the length of AD is

In the Delta ABC, D and E are points on side AB and AC respectively such that DE II BC. If AE=2cm, AD=3cm and BD=4.5cm, then find CE.

ABCD is a trapezium in which AB abs() DC and P,Q are points on AD and BC respectively, such that PQ abs() DC, if PD=18 cm, BQ=35 cm and QC=15 cm. Find AD.

In triangle ABC E and D are points on sides AB and AC,respectively, such that angle ABC= angle ADE , if AE = 6cm, AD = 4 cm and EB = 4 cm, then the length of DC is: triangle ABC में, E और D क्रमशः AB और AC पर एक बिंदु हैं, जैसे कि angle ABC= angle ADE ,यदि AE = 6cm, AD = 4 cm और EB = 4 cm है, तो DC की लंबाई है:

If D and E are points on the sides AB and AC respectively of DetlaABC such that AB=5.6 cm, AD=1.4 cm, AC=7.2 cm and AE=1.8cm . Show that DE||BC .

D and E are points on the sides AB and AC respectively such that AB=3.6cm and AD=1.4AC=7.2 and AE=1.8. Show that DE is parallel to BC