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Metallic spheres of radii 6cm, 8 cm and 10cm, respectively are melted to form a single solid sphere. Find the radius of the resulting sphere.

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To find the radius of the resulting sphere formed by melting three metallic spheres with given radii, we will follow these steps: ### Step 1: Calculate the volumes of the individual spheres The volume \( V \) of a sphere is given by the formula: \[ V = \frac{4}{3} \pi r^3 \] where \( r \) is the radius of the sphere. For the three spheres: - For the first sphere with radius \( r_1 = 6 \) cm: \[ V_1 = \frac{4}{3} \pi (6)^3 = \frac{4}{3} \pi (216) = 288 \pi \, \text{cm}^3 \] - For the second sphere with radius \( r_2 = 8 \) cm: \[ V_2 = \frac{4}{3} \pi (8)^3 = \frac{4}{3} \pi (512) = \frac{2048}{3} \pi \, \text{cm}^3 \] - For the third sphere with radius \( r_3 = 10 \) cm: \[ V_3 = \frac{4}{3} \pi (10)^3 = \frac{4}{3} \pi (1000) = \frac{4000}{3} \pi \, \text{cm}^3 \] ### Step 2: Find the total volume of the spheres Now, we can find the total volume \( V \) of the resulting sphere by adding the volumes of the three spheres: \[ V = V_1 + V_2 + V_3 \] Substituting the values we calculated: \[ V = 288 \pi + \frac{2048}{3} \pi + \frac{4000}{3} \pi \] To add these, we need a common denominator. The common denominator for the fractions is 3: \[ V = 288 \pi + \left(\frac{2048 + 4000}{3}\right) \pi \] Calculating the sum inside the parentheses: \[ 2048 + 4000 = 6048 \] So, \[ V = 288 \pi + \frac{6048}{3} \pi = 288 \pi + 2016 \pi = (288 + 2016) \pi = 2304 \pi \, \text{cm}^3 \] ### Step 3: Find the radius of the resulting sphere The volume of the resulting sphere can also be expressed as: \[ V = \frac{4}{3} \pi R^3 \] where \( R \) is the radius of the resulting sphere. Setting the two expressions for volume equal gives: \[ \frac{4}{3} \pi R^3 = 2304 \pi \] Dividing both sides by \( \pi \): \[ \frac{4}{3} R^3 = 2304 \] Multiplying both sides by \( \frac{3}{4} \): \[ R^3 = 2304 \times \frac{3}{4} = 1728 \] Now, taking the cube root of both sides: \[ R = \sqrt[3]{1728} = 12 \, \text{cm} \] ### Final Answer The radius of the resulting sphere is \( 12 \) cm. ---
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