Home
Class 10
MATHS
DeltaABC ~ DeltaDEF. Their areas are 64 ...

`DeltaABC ~ DeltaDEF`. Their areas are `64 cm^2 and 121cm^2`. If `EF = 12.1 cm`, then value of BC is :

A

8.8 cm

B

12.1

C

12.4 cm

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use the properties of similar triangles and the relationship between their areas and corresponding sides. ### Step-by-Step Solution: 1. **Identify the Given Information:** - Area of triangle ABC = 64 cm² - Area of triangle DEF = 121 cm² - Length of side EF = 12.1 cm 2. **Use the Ratio of Areas:** Since triangles ABC and DEF are similar, the ratio of their areas is equal to the square of the ratio of their corresponding sides. Therefore, we can write: \[ \frac{\text{Area of } \Delta ABC}{\text{Area of } \Delta DEF} = \left(\frac{BC}{EF}\right)^2 \] 3. **Substituting the Areas:** Substitute the given areas into the equation: \[ \frac{64}{121} = \left(\frac{BC}{12.1}\right)^2 \] 4. **Taking the Square Root:** Taking the square root of both sides gives: \[ \frac{\sqrt{64}}{\sqrt{121}} = \frac{BC}{12.1} \] Simplifying the square roots: \[ \frac{8}{11} = \frac{BC}{12.1} \] 5. **Cross-Multiplying to Solve for BC:** Now we cross-multiply to find BC: \[ 8 \cdot 12.1 = 11 \cdot BC \] \[ 96.8 = 11 \cdot BC \] 6. **Dividing to Isolate BC:** Now, divide both sides by 11: \[ BC = \frac{96.8}{11} \] Calculating this gives: \[ BC = 8.8 \text{ cm} \] ### Final Answer: The length of side BC is **8.8 cm**. ---
Promotional Banner

Topper's Solved these Questions

  • MBD NEW STYPE MODEL TEST PAPER - 2

    MBD -HARYANA BOARD|Exercise SET - A (SECTION -B)|4 Videos
  • MBD NEW STYPE MODEL TEST PAPER - 2

    MBD -HARYANA BOARD|Exercise SET - A (SECTION -C)|5 Videos
  • MBD NEW STYLE MODEL TEST PAPER -1

    MBD -HARYANA BOARD|Exercise SET - D (SECTION - D)|4 Videos
  • PAIR OF LINEAR EQUATIONS IN TWO VARIABLES

    MBD -HARYANA BOARD|Exercise SHORT ANSWER TYPE QUESTIONS|20 Videos

Similar Questions

Explore conceptually related problems

Let DeltaABC~ DeltaDEF and their areas be respectively 64 cm^(2) and 121 cm^(2) . If EF = 15.4 cm find BC .

Let ABC ~ triangle DEF and their areas be 81 cm^(2) and 144 cm^(2) . If EF = 24 cm, then length of side BC is ……………………. Cm

Let DeltaABC-DeltaDEF and their areas be , respectively , 64cm^(2)and 121cm^(2) . If EF=15.4 cm , find BC.

DeltaABC and DeltaDEF are similar and their areas be respectively 64cm^(2) and 121cm^(2) . If EF=15.4cm , BC is.

Let DeltaABC -DeltaDEF , ar(DeltaABC)= 169 cm^(2) and ar (DeltaDEF) = 121 cm^(2) . If AB = 26 cm thhen find DE.

DeltaABC and DeltaDEF are two similar triangle and the primeters of DeltaABC and DeltaDEF are 30 cm and 18 cm respectively . If the length of DE = 36 cm , then length of AB is

It is given that DeltaABC ~ DeltaEDF and Area DeltaABC : Area DeltaDEF = 64: 25 . If AB = 16 cm, BC = 18 cm, CA= 20 cm. What is the value of EF (in cm)?

If DeltaABC ~ DeltaDEF AB =4 cm , DE = 6 cm, EF =9 cm and FD =12 cm find the perimeter of DeltaABC .

Delta ABC~DeltaDEC such that ar(Delta ABC)=64 cm^(2) and ar (Delta DEF)=169 cm^(2) . If BC=4 cm , find EF.