[" (iv) "bx+cy=a+b],[ax((1)/(a-b)-(1)/(a+b))+cy((1)/(b-a)-(1)/(b+a))=(2a)/(a+b)],[" a "]

Solve the following system of equations by method of cross-multiplication: bx+cy=a+b,quad and ax((1)/(a-b)-(1)/(a+b))+cy((1)/(b-a)-(1)/(b+a))=(2a)/(a+b)

(a)/(ax-1)+(b)/(bx-1)=a+b,x!=(1)/(a),(1)/(b)

Solve for x:(a)/(ax-1)+(b)/(bx-1)=a+b;x!=(1)/(a),(1)/(b)

Solve: a/(ax-1)+b/(bx-1)=a+b (x!=1/a,1/b) .

{:(ax + by = 1),(bx + ay = ((a + b)^(2))/(a^(2) + b^(2))-1):}

{:(ax + by = 1),(bx + ay = ((a + b)^(2))/(a^(2) + b^(2))-1):}

If the roots of the equation (x^(2)-bx)/(ax-c)=(m-1)/(m+1) are equal to opposite sign,then the value of m will be (a-b)/(a+b) b.(b-a)/(a+b) c.(a+b)/(a-b) d.(b+a)/(b-a)

Solve for x: a/(ax-1)+b/(bx-1)=a+b; x!= 1/a, 1/b

Solve each of the following quadratic equations: (a)/((ax-1))+(b)/((bx-1))=(a+b),xne(1)/(a),(1)/(b)

If (1)/((a^(2)-bx)(b^(2)-ax))=(A)/(a^(2)-bx)+(B)/(b^(2)-bx) , then the value of A and B respectively would be _________.