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Assertion (A): Least count of all screw ...

Assertion (A): Least count of all screw based instruments is same.
Reason (R ): Least count for all screw based instruments are found using the ratio of pitch per division of circular scale.

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Assertion : A screw gauge having a smaller value of pitch has greater accuracy. Reason : The least count of screw gauge is directly proportional to the number of divisions on circular scale.

Assertion : A screw gauge having a smaller value of pitch has greater accuracy. Reason : The least count of screw gauge is directly proportional to the number of divisions on circular scale.

Pitch of a screw gauge is 0.5 mm and its least count is .01 mm, Calculate no. of divisons on its circular scale.

How are pitch and least count of a screw gauge related to each other?

The meehanism behind nut and bolt arrangement also works for screw gauge. In case of nut and bolt mechanism, with rotation of bolt, it has translational movement also. In one complete rotation of bolt, tip of bolt moves by a linear distance equal to linear distance between two consecutive threads on the screw, known as pitch in case of screw gauge, the circular scale is divided in several parths. The ratio of pitch and total number of divisions on circular scale is known as least count. Spherometer is a device used to measure very small distances such as radius of curvature and thicness of thin plate. The screw gauge can be used to meaure diameter of a spherical sample. A screw gauge has 100 divisions on head scale and in 8 rotations distance covered is 8 mm. Least count of given screw gauge is

Pitch of a screw gauze instrument is 0.5 mm and its circular scale is divided into 100 divisions. The least count of the instrument will be

The pitch of a screw gauge is 0.5 mm. It's head scale contains 50 divisions. The least count of the screw gauge is

The pitch of a screw gauge is 0.5 mm. It's head scale contains 50 divisions. The least count of the screw gauge is

Write the expression for pitch and least count a screw gauge.