A charged particle moves with velocity `vec v = a hat i + d hat j` in a magnetic field `vec B = A hat i + D hat j.` The force acting on the particle has magnitude F. Then,

An alpha particle moving with the velocity vec v = u hat i + hat j ,in a uniform magnetic field vec B = B hat k . Magnetic force on alpha particle is

An alpha particle moving with the velocity vec v = u hat i + hat j ,in a uniform magnetic field vec B = B hat k . Magnetic force on alpha particle is

A charged particle has acceleration vec a = 2 hat i + x hat j in a megnetic field vec B = - 3 hat i + 2 hat j - 4 hat k. Find the value of x.

A charged particle has acceleration vec a = 2 hat i + x hat j in a megnetic field vec B = - 3 hat i + 2 hat j - 4 hat k. Find the value of x.

An alpha particle is moving with a velocity of (7 xx 10^(5) hat I m//s) in a magnetic field of (5 hat I + 9 hat j) T. Find the magnetic force acting on the particle.

An alpha particle is moving with a velocity of (7 xx 10^(5) hat i m//s) in a magnetic field of (5 hat i + 9 hat j ) . T . Find the magnetic force acting on the particle.

A charged particle of specific charge (charge/mass) alpha released from origin at time t=0 with velocity vec v = v_0 (hat i + hat j) in uniform magnetic field vec B = B_0 hat i. Coordinates of the particle at time t= pi//(B_0 alpha) are

The velocity of a particle of mass 2 kg is given by vec(v)=at hat(i)+bt^(2)hat(j) . Find the force acting on the particle.

A particle has initial velocity vec(v)=3hat(i)+4hat(j) and a constant force vec(F)=4hat(i)-3hat(j) acts on the particle. The path of the particle is :