A liquid is flowing through a horizontal channel. The speed of flow (v) depends on height (y) from the floor as `v=v_(0)[2((y)/(h))-((y)/(h))^(2)]`.Where h is the height of liquid in the channel and `v_(0)` is the speed of the top layer. Coefficient of viscosity is `eta`. Calculate the shear stress that the liquid exerts on the floor.

A liquid is flowing through a horizontal channel. The speed of flow (v) depends on height (y) from the floor as v = v_(0)[2((y)/(h))-((y)/(h))^(2)] . Where h is the height of liquid in the channel and v_(0) is the speed of the top layer. Coefficient of viscosity is eta . Then the shear stress that the liquid exerts on the floor is.

A liquid is flowing through a horizontal channel. The speed of flow (v) depends on height (y) from the floor as v = v_(0)[2((y)/(h))-((y)/(h))^(2)] . Where h is the height of liquid in the channel and v_(0) is the speed of the top layer. Coefficient of viscosity is eta . Then the shear stress that the liquid exerts on the floor is.

An incompressible liquid is flowing through a horizontal pipe as shown in figure. The value of speed v is

An incompressible liquid is flowing through a horizontal pipe as shown in figure. The value of speed v is

A vertical steel rod has radius a. The rod has a coat of a liquid film on it. The liquid slides under gravity. It was found that the speed of liquid layer at radius r is given by v=(rhogb^(2))/(2eta)ln((r)/(a))-(rhog)/(4eta)(r^(2)-a^(2)) Where b is the outer radius of liquid film, eta is coefficient of viscosity and rho is density of the liquid. (i) Calculate the force on unit length of the rod due to the viscous liquid? (ii) Set up the integral to calculate the volume flow rate of the liquid down the rod. [you may not evaluate the integral]

If V_(1) and V_(2)D be the volumes of the liquids flowing out of the same tube in the same interval of time and eta_(1) and eta_(2) their coefficients of viscosity respectively then

A liquid flows through a horizontal tube. The velocities of the liquid in the two sections, which have areas of cross section A_(1) and A_(2) are v_(1) and v_(2) respectively. The difference in the levels of the liquid in the two vertical tubes is h . Then

A liquid flows through a horizontal tube. The velocities of the liquid in the two sections, which have areas of cross section A_(1) and A_(2) are v_(1) and v_(2) respectively. The difference in the levels of the liquid in the two vertical tubes is h . Then

A liquid flows through a horizontal tube. The velocities of the liquid in the two sections, which have areas of cross section A_(1) and A_(2) are v_(1) and v_(2) respectively. The difference in the levels of the liquid in the two vertical tubes is h . Then

Check the correctness of the relation V=(pipr^(4))/(8etal) where V is the volume per unit time of a liquid flowing through a tube of radius r and length l, eta is the coefficient of viscosity of the liquid and p is the pressure difference between the ends of the tube.