" (b) "(bx)/(a)-(ay)/(b)+a+b=0" and "bx-ay+2ab=0

Solve the following system of equations b(x)/(a)-a(y)/(b)+a+b=0,bx-ay+2ab=0

The equation of a line perpendicular to line ax+by+c=0 and passing through (a,b) is equal to ................ A) bx-ay=0 B) bx+ay-2ab=0 C) bx+ay=0 D) bx-ay+ 2ab=0

ax+by=a-b;bx-ay=a+b

(ax+by)^(2)-(ay+bx)^(2)

(bx ) /(a) + ( ay ) /( b) = a ^(2) + b ^(2) , x + y = 2ab

The straight line x-y-2=0 cuts the axis of x at A. It is rotated about A in such a manner that it is perpendicular to ax+by+c=0. Its equation is: (a) bx-ay-2b=0 (b) ax-by-2a=0 (c) bx+ay-2b=0 (d) ax+by+2a=0

If a !=b , then the system of equation ax + by + bz = 0 bx + ay + bz = 0 and bx + by + az = 0 will have a non-trivial solution, if

If a !=b , then the system of equation ax + by + bz = 0 bx + ay + bz = 0 and bx + by + az = 0 will have a non-trivial solution, if

If the lines ax + by + c = 0, bx + cy + a = 0 and cx + ay + b = 0 be concurrent, then: