[cos theta+cos^(2)theta=1],[a sin^(12)theta+b sin^(10)theta+csin^(8)theta],[+d sin^(6)theta=1rArr(b+c)/(a+d)=]

cos theta+cos^(2)theta=1,a sin^(12)theta+b sin^(10)theta+c sin^(8)theta+d sin^(6)theta=1rArr(b+c)/(a+d)=

If cos theta+cos^(2)theta=1, prove that sin^(12)theta+3sin^(10)theta+3sin^(8)theta+sin^(6)theta+2sin^(4)theta+2sin^(2)theta-2=1

If Sin theta+ Sin^(2) theta=1 and cos a cos^(12) theta+ b cos ^(12) theta+ b cos^(10) theta+ c cos^(8) theta+d cos^(6)-1 theta = then (b+c)/(a+d)

If sin theta + sin ^(2) theta =1 and cos ^(12) theta + a cos ^(10) theta + bcos ^(8) theta + c cos ^(6) theta + d =0, then

If sin theta+sin ^(2) theta=1 then cos ^(12) theta+3 cos ^(10) theta+3 cos ^(8) theta+cos ^(6) theta=

If sin theta + sin^(2) theta =1 then cos^(4) theta + cos^(8) theta + 2 cos^(6) theta =

int(sin^(6)theta+cos^(6)theta)/(sin^(2)theta cos^(2)theta)d theta=

The value of 3(cos theta-sin theta)^(4)+6(sin theta+cos theta)^(2)+4 sin^(6) theta is where theta in ((pi)/(4),(pi)/(2)) (a) 13-4cos^(4) theta (b) 13-4cos^(6) theta (c) 13-4cos^(6) theta+ 2 sin^(4) theta cos^(2) theta (d) 13-4cos^(4) theta+ 2 sin^(4) theta cos^(2) theta

The value of 3(cos theta-sin theta)^(4)+6(sin theta+cos theta)^(2)+4 sin^(6) theta is where theta in ((pi)/(4),(pi)/(2)) (a) 13-4cos^(4) theta (b) 13-4cos^(6) theta (c) 13-4cos^(6) theta+ 2 sin^(4) theta cos^(2) theta (d) 13-4cos^(4) theta+ 2 sin^(4) theta cos^(2) theta