` 9 + 20 i `

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Let's solve : 9x + 2 = 20

I. x^(2) + 9x + 20 = 0" "II. Y^(2) = 16

I. 2x^(2) + 5x + 2 = 0" "II. Y^(2) + 9y + 20 = 0

I. x^(2) - 10x+24 = 0 II. y^(2) - 9y + 20 = 0

I. 20x^(2) - x - 12 = 0 II. 20y^(2) + 27y + 9 = 0

Find the value of n if (i) ( n + 1) ! = 20 ( n-1 ) ! ( ii) 1/( 8!) + 1/( 9 !) = n/( 10 !)

I. 20x^(2) + 9x+1 = 0" " II. 30y^(2) + 11y + 1= 0

If Z = x^2 - 7x - 9yi such that bar Z = y^2 i + 20i - 12 then the number of order pair (x,y) is :

1, 4, 9, 16, 20, 36, 49 (a) 1 (b) 9 (c) 20 (d) 49